F(x)=2-3x+4x^2

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Solution for F(x)=2-3x+4x^2 equation: 



(F)=2-3F+4F^2

We move all terms to the left:

(F)-(2-3F+4F^2)=0

We get rid of parentheses

-4F^2+3F+F-2=0

We add all the numbers together, and all the variables

-4F^2+4F-2=0

a = -4; b = 4; c = -2;
Δ = b2-4ac
Δ = 42-4·(-4)·(-2)
Δ = -16
Delta is less than zero, so there is no solution for the equation

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